document.write( "Question 899353: The annual interest on a $15,000 investment exceeds the amount of interest earned by a $1000 investment by $410. The $15,000 is invested at a .4% higher rate of interest than the $1000 investment. What is the rate of interest for each investment?\r
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Algebra.Com's Answer #545308 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
let interest rate on $1000 be x\r
\n" ); document.write( "\n" ); document.write( "15000 @ (x+4)%\r
\n" ); document.write( "\n" ); document.write( "interest earned on 15000 less interest earned on 1000 = 410\r
\n" ); document.write( "\n" ); document.write( "15000*(x+4)% -1000*x%=410\r
\n" ); document.write( "\n" ); document.write( "multiply by 100\r
\n" ); document.write( "\n" ); document.write( "15000(x+4)-1000x= 41000\r
\n" ); document.write( "\n" ); document.write( "15000x+60000-1000x=41000\r
\n" ); document.write( "\n" ); document.write( "there appears to be a typo in the problem
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