document.write( "Question 899335: \n" ); document.write( "
Algebra.Com's Answer #545306 by MathTherapy(10552)\"\" \"About 
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last month mrs santos bought x kilos of fish for 600 today she paid the same amount but got 3 kilos less due to price increase of 45 per kilo. Find the value of x and the original price of a kilo of fish?\r
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document.write( "Amount purchased last month: x kilos
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document.write( "Since last month, she bought x kilos for 600, she paid \"600%2Fx\", per kilo, then 
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document.write( "Since today, she bought x – 3 kilos for 600, she paid \"600%2F%28x+-+3%29\", per kilo
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document.write( "Since there was a 45 per kilo increase, then we have: \"600%2Fx+%2B+45+=+600%2F%28x+-+3%29\"
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document.write( "600(x – 3) + 45(x)(x - 3) = 600(x) ------- Multiplying by LCD, x(x – 3)
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document.write( "\"600x+-+1800+%2B+45x%5E2+-+135x+=+600x+\"
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document.write( "\"45x%5E2+-+600x+%2B+600x+-+135x+-+1800+=+0\"
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document.write( "\"45x%5E2+-+135x+-+1800+=+0\"
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document.write( "\"45%28x%5E2+-+3x+-+40%29+=+45%280%29\" ------ Factoring out GCF, 45 
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document.write( "\"x%5E2+-+3x+-+40+=+0\"
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document.write( "(x - 8)(x + 5) = 0 
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document.write( "x, or original amount purchased = \"highlight_green%288%29\" kilos		OR		x = - 5 (ignore)
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document.write( "Original price of 1 kilo: \"600%2F8\", or \"highlight_green%2875%29\"
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document.write( "You can do the check!! \r
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