document.write( "Question 898789: larry has an annual return of $213 from $3000 invested at simple interest, some at 5% the rest at 8%. how much was invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #545294 by richwmiller(17219) $\"\"$ $\"About$

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x+y=3000,
\n" ); document.write( "0.05*x+0.08*y=213
\n" ); document.write( "x=3000-y
\n" ); document.write( "0.05*(3000-y)+0.08*y=213
\n" ); document.write( "150-0.05y+0.08*y=213
\n" ); document.write( "0.03*y=63
\n" ); document.write( "y= 2100
\n" ); document.write( "x=3000-y
\n" ); document.write( "x=900
\n" ); document.write( "check
\n" ); document.write( "0.05*900+0.08*2100=213
\n" ); document.write( "45+168=213
\n" ); document.write( "213=213
\n" ); document.write( "ok
\n" ); document.write( " \n" ); document.write( "

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