document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=75925>Question 75925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i graph -2f(x+1)-3 when f(x)= the absolute value of x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #54529 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=54529\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how do i graph -2f(x+1)-3 when f(x)= the absolute value of x<BR>\n" );
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document.write( "Let's assume you know that f(x)=|x| looks like<BR>\n" );
document.write( "a \"V\" with the bottom point at (0,0).<BR>\n" );
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document.write( "The \"(x+1)\" moves the entire graph 1 to the left so<BR>\n" );
document.write( "the bottof of the V is at (-1,0)<BR>\n" );
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document.write( "The \"-2\" flips it over the x-axis so not the tip of<BR>\n" );
document.write( "the V is still at (-1,0) but the V is upside down.<BR>\n" );
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document.write( "The \"-3\" lovers all the points of the graph so the<BR>\n" );
document.write( "tip of the V is now at (-1,-3).<BR>\n" );
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document.write( "Hope that helps.<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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