document.write( "Question 75925: how do i graph -2f(x+1)-3 when f(x)= the absolute value of x \n" ); document.write( "
Algebra.Com's Answer #54529 by stanbon(75887)\"\" \"About 
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how do i graph -2f(x+1)-3 when f(x)= the absolute value of x
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\n" ); document.write( "Let's assume you know that f(x)=|x| looks like
\n" ); document.write( "a \"V\" with the bottom point at (0,0).
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\n" ); document.write( "The \"(x+1)\" moves the entire graph 1 to the left so
\n" ); document.write( "the bottof of the V is at (-1,0)
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\n" ); document.write( "The \"-2\" flips it over the x-axis so not the tip of
\n" ); document.write( "the V is still at (-1,0) but the V is upside down.
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\n" ); document.write( "The \"-3\" lovers all the points of the graph so the
\n" ); document.write( "tip of the V is now at (-1,-3).
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\n" ); document.write( "Hope that helps.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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