document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=899184>Question 899184</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The second angle in a triangle is three times as large as the first. The third angle is one third as large as the second angle. Find the angle measures. Draw a possible picture of the triangle.\r<BR>\n" );
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document.write( "I came up with this equation but I dont think its right or im not working the math correctly because my measurements come out weird.\r<BR>\n" );
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document.write( "X+3x+(1/3)× X=180 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545253 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x+3x+3x*1/3=180<BR>\n" );
document.write( "5x=180<BR>\n" );
document.write( "x=180/5<BR>\n" );
document.write( "x=36<BR>\n" );
document.write( "3x=108<BR>\n" );
document.write( "3x*1/3=36 </SPAN>\n" );
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