document.write( "Question 899025: The area of a right triangle is 99 square feet. The length of the triangle is 4 feet larger than the width. What is the width of the triangle. Type the larger of your two answers as a decimal rounded to the nearest hundredth. Note: The area of a triangle equals 0.5(length)(width). \n" ); document.write( "

Algebra.Com's Answer #545143 by mananth(16946) $\"\"$ $\"About$

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let width be x
\n" ); document.write( "length = (x+4)\r
\n" ); document.write( "\n" ); document.write( "it is a right triangle\r
\n" ); document.write( "\n" ); document.write( "(1/2)x*(x+4)=99\r
\n" ); document.write( "\n" ); document.write( "multiply by 2
\n" ); document.write( "x(x+4)=198\r
\n" ); document.write( "\n" ); document.write( "x^2+4x=198
\n" ); document.write( "x^2+4x-198=0\r
\n" ); document.write( "\n" ); document.write( "solve quadratic \r
\n" ); document.write( "\n" ); document.write( "Find the roots of the equation by quadratic formula
\n" ); document.write( "
\n" ); document.write( "Find the roots of the equation by quadratic formula
\n" ); document.write( "
\n" ); document.write( "a= 1 , b= 4 , c= -198
\n" ); document.write( "
\n" ); document.write( "b^2-4ac= 16 + 792
\n" ); document.write( "b^2-4ac= 808
\n" ); document.write( " $\"%09sqrt%28%09808%09%29=%0928.43%09\"$
\n" ); document.write( " $\"x=%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( " $\"x1=%28-b%2Bsqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( "x1=( -4 + 28.43 )/ 2
\n" ); document.write( "x1= 12.21
\n" ); document.write( " $\"x2=%28-b-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"$
\n" ); document.write( "x2=( -4 -28.43 ) / 2
\n" ); document.write( "x2= -16.21
\n" ); document.write( "Ignore negative value
\n" ); document.write( "x= 12.21 \r
\n" ); document.write( "\n" ); document.write( "12.21 & 16.21
\n" ); document.write( "
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