document.write( "Question 899007: How can Php 42,000 be invested part at 4% and rest at 7% to makr a yearly interest equal to 5% of Php 42,000 \n" ); document.write( "

Algebra.Com's Answer #545106 by mananth(16946) $\"\"$ $\"About$

You can put this solution on YOUR website!
Part I 4.00% per annum ------------- Amount invested =x
\n" ); document.write( "Part II 7.00% per annum ------------ Amount invested = y
\n" ); document.write( " 42000
\n" ); document.write( "Interest----- 2100.00
\n" ); document.write( "
\n" ); document.write( "Part I 4.00% per annum ---x
\n" ); document.write( "Part II 7.00% per annum ---y
\n" ); document.write( "Total investment
\n" ); document.write( "x + 1 y= 42000 -------------1
\n" ); document.write( "Interest on both investments
\n" ); document.write( "4.00% x + 7.00% y= 2100
\n" ); document.write( "Multiply by 100
\n" ); document.write( "4 x + 7 y= 210000.00 --------2
\n" ); document.write( "Multiply (1) by -4
\n" ); document.write( "we get
\n" ); document.write( "-4 x -4 y= -168000.00
\n" ); document.write( "Add this to (2)
\n" ); document.write( "0 x 3 y= 42000
\n" ); document.write( "divide by 3
\n" ); document.write( " y = 14000
\n" ); document.write( "Part I 4.00% $ 28000
\n" ); document.write( "Part II 7.00% $ 14000
\n" ); document.write( "
\n" ); document.write( "CHECK
\n" ); document.write( "28000 --------- 4.00% ------- 1120.00
\n" ); document.write( "14000 ------------- 7.00% ------- 980.00
\n" ); document.write( "Total -------------------- 2100.00
\n" ); document.write( "
\n" ); document.write( "m.ananth@hotmail.ca
\n" ); document.write( " \n" ); document.write( "

\n" );