document.write( "Question 898980: a) A manufacturer claims that his market share is sixty percent. However a random sample of two hundred customers reveals that only one hundred and ten are users of his product. Test the manufacturer’s claim at one percent level of significance and interpret your results \n" ); document.write( "
Algebra.Com's Answer #545098 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "Hi
\n" ); document.write( "Ho: p = 0.6 (claim)
\n" ); document.write( "Ha: p < 0.4 \r
\n" ); document.write( "\n" ); document.write( "sample proportion = p-hat = 110/200= .55
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\n" ); document.write( "test stat:: z(0.55) = (0.55-0.6)/sqrt[0.6*0.4/200] = -.05/.0346 = -1.4438
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\n" ); document.write( "p-value = P(z < -1.4438) = 0.0744 0r 7.44%
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\n" ); document.write( "Conclusion:
\n" ); document.write( "Since the p-value is greater than 1%, accept Ho.
\n" ); document.write( "The test results support the claim.
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