document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=898964>Question 898964</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a rectangular field is 94m^2. its perimeter is 38 meters. find the dimension of the field. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545075 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39618)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545075\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Try solving this in general.<BR>\n" );
document.write( "A for area, p for perimeter.<BR>\n" );
document.write( "Dimensions x and y.\r<BR>\n" );
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document.write( "Rectangle.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=xy=A ALIGN=MIDDLE  ALT=\"xy=A\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2B2y=p ALIGN=MIDDLE  ALT=\"2x%2B2y=p\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "Assume A and p are known.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2y=p-2x ALIGN=MIDDLE  ALT=\"2y=p-2x\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%28p-2x%29%2F2 ALIGN=MIDDLE  ALT=\"y=%28p-2x%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=p%2F2-x ALIGN=MIDDLE  ALT=\"y=p%2F2-x\"   DISABLED_style= \"max-width:90%; height:auto;\" >------substitute this into the area equation.<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%28p%2F2-x%29=A ALIGN=MIDDLE  ALT=\"x%28p%2F2-x%29=A\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28P%2F2%29x-x%5E2-A=0 ALIGN=MIDDLE  ALT=\"%28P%2F2%29x-x%5E2-A=0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=-x%5E2%2B%28p%2F2%29x-A=0 ALIGN=MIDDLE  ALT=\"-x%5E2%2B%28p%2F2%29x-A=0\"   DISABLED_style= \"max-width:90%; height:auto;\" > and multiply both members by -1.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28x%5E2-%28p%2F2%29x%2BA=0%29 ALIGN=MIDDLE  ALT=\"highlight_green%28x%5E2-%28p%2F2%29x%2BA=0%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "which, if you substitute for the values of p and A now, you might find that the<BR>\n" );
document.write( "quadratic expression is factorable; but you do not always have this condition.\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=%28p%2F2%2B-+sqrt%28%28p%2F2%29%5E2-4%2AA%29%29%2F2 ALIGN=MIDDLE  ALT=\"x=%28p%2F2%2B-+sqrt%28%28p%2F2%29%5E2-4%2AA%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "You most likely want the PLUS square root form;<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28x=%28p%2F2%2Bsqrt%28%28p%2F2%29%5E2-4A%29%29%2F2%29 ALIGN=MIDDLE  ALT=\"highlight%28x=%28p%2F2%2Bsqrt%28%28p%2F2%29%5E2-4A%29%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Use the area equation to solve for y.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=A%2Fx ALIGN=MIDDLE  ALT=\"y=A%2Fx\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%2F%28%28p%2F2%2Bsqrt%28%28p%2F2%29%5E2-4A%29%29%2F2%29 ALIGN=MIDDLE  ALT=\"A%2F%28%28p%2F2%2Bsqrt%28%28p%2F2%29%5E2-4A%29%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28y=%282A%29%2F%28p%2F2%2Bsqrt%28%28p%2F2%29%5E2-4A%29%29%29 ALIGN=MIDDLE  ALT=\"highlight%28y=%282A%29%2F%28p%2F2%2Bsqrt%28%28p%2F2%29%5E2-4A%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "You can substitute for A and p early and avoid pure symbolic form, but if the quadratic expression is<BR>\n" );
document.write( "not factorable, the solution in pure symbolic form will work for all problems of this general kind.<BR>\n" );
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