document.write( "Question 898920: Drug Concentration. When a pharmaceutical drug is injected into the bloodstream, it's concentration at time t can be approximated by C(t) = C0(e)^-kt, where C0 is is the concentration at t = 0. Suppose the drug is ineffective below a concentration C1 and harmful above concentration C2. Then it can be shown that the drug should be given at intervals of the time T. Where T = (1/k)ln(C2/C1).\r
\n" ); document.write( "\n" ); document.write( "A certain drug is harmful at a concentration five times the concentration below which it is ineffective. At noon an injection of the drug result in a concentration of 2 mg per liter of blood. Three hours later the concentration is down to 1 mg per liter. How often should the drug be given?
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Algebra.Com's Answer #545045 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
\"At noon an injection...\" gives the data to find k in the first equation.
\n" ); document.write( "\"C%2FCo=e%5E%28-kt%29\"
\n" ); document.write( "\"ln%28C%2FCo%29=-kt%2Aln%28e%29\"
\n" ); document.write( "\"ln%28C%2FCo%29=-kt\"
\n" ); document.write( "\"k=-%281%2Ft%29ln%28C%2FCo%29\"
\n" ); document.write( "\"highlight_green%28k=%281%2Ft%29ln%28Co%2FC%29%29\"
\n" ); document.write( "The variable choices are slightly different than yours.
\n" ); document.write( "The data in the rest of that sentence and the next one put into this formula makes \"k=%281%2F3%29ln%282%29\".
\n" ); document.write( "\"highlight_green%28k=0.231%29\".\r
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\n" ); document.write( "\n" ); document.write( "Knowing the value for k allows you to find the value for T, the time interval between effective and harmful. Now, using YOUR choice of variables, C2=5*C and C1=C in this case for some constant C. This gives \"T=%281%2Fk%29ln%285%29\",
\n" ); document.write( "\"T=%281%2F0.231%29ln%285%29\"
\n" ); document.write( "\"highlight%28T=6.97%29\", not sure if to the nearest hour might be best or not; but this could be stated T is 6 hours and 58 minutes.
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