document.write( "Question 898917: A bicyclist travels at a constant rate on her bicylce. Biking with the wind, it takes 2.6 hours to travel 52 miles. Biking against the wind, the return trip takes 4 hours. If there was no wind, how fast was the cyclist biking? \n" ); document.write( "

Algebra.Com's Answer #545040 by stanbon(75887) $\"\"$ $\"About$

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A bicyclist travels at a constant rate on her bicylce. Biking with the wind, it takes 2.6 hours to travel 52 miles. Biking against the wind, the return trip takes 4 hours. If there was no wind, how fast was the cyclist biking
\n" ); document.write( "---------------------
\n" ); document.write( "With Wind DATA:
\n" ); document.write( "distance = 52 miles ; time = 2.6 hrs ; rate = 52/2.6 = 20 mph
\n" ); document.write( "----
\n" ); document.write( "Against wind DATA:
\n" ); document.write( "distance = 52 miles ; time = 4 hrs ; rate = 52/4 = 13 mph
\n" ); document.write( "-----
\n" ); document.write( "Equations:
\n" ); document.write( "b + w = 20 mph
\n" ); document.write( "b - w = 13 mph
\n" ); document.write( "-----
\n" ); document.write( "Add and solve for \"b\"::
\n" ); document.write( "2b = 33
\n" ); document.write( "b = 16.5 mph (speed with no wind)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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