document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1634>Question 1634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am a father who has not used algebra since 1972!!  My daughter ia having an issue with, How to solve an equation using fractions.  ie: \"1/3x+2=6\"  I am stumped. can you break it down for us.\r<BR>\n" );
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document.write( "Thanx.\r<BR>\n" );
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document.write( "Glenn </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #545 by </B><A HREF=/tutors/aboutme.mpl?userid=Carlos.Granados><B>Carlos.Granados(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Carlos.Granados><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=545\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You can do it this way also:<BR>\n" );
document.write( "Start canceling positives or negatives isolating the X. Here substract 2 in bouth sides so the +2 that is on the X side cancels.<BR>\n" );
document.write( "1/3X + 2 -2 = 6 -2<BR>\n" );
document.write( "1/3X        = 4<BR>\n" );
document.write( "Now you can cancel 1/3 by the opposite, multiply that by 3 in bouth sides two then:\r<BR>\n" );
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document.write( "3 * 1/3X    = 4 * 3<BR>\n" );
document.write( "3/3X        = 12<BR>\n" );
document.write( "Three over Three cancels<BR>\n" );
document.write( "X = 12<BR>\n" );
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