document.write( "Question 898741: Each interior angle of a regular polygon is thrice each exterior angle.
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document.write( "Find the number of side of the polygon. \n" );
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Algebra.Com's Answer #544981 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! Each interior angle of a regular polygon is thrice each exterior angle. \n" ); document.write( "Find the number of side of the polygon. \n" ); document.write( " \r\n" ); document.write( "An interior angle and an exterior angle at a vertex of a polygon\r\n" ); document.write( "are supplementary.\r\n" ); document.write( "\r\n" ); document.write( "Let the exterior angle be X.\r\n" ); document.write( "Then the interior angle is 3X.\r\n" ); document.write( "Since they are supplementary,\r\n" ); document.write( "\r\n" ); document.write( "X + 3X = 180°\r\n" ); document.write( " 4X = 180°\r\n" ); document.write( " X = 45°\r\n" ); document.write( "\r\n" ); document.write( "So each exterior angle is 45°, and each interior angle is 3×45°=135°.\r\n" ); document.write( "\r\n" ); document.write( "Let the number of sides be N.\r\n" ); document.write( "\r\n" ); document.write( "The sum of the exterior angles of a polygon is 360°\r\n" ); document.write( "\r\n" ); document.write( "Since the polygon is regular, each interior angle is\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |