document.write( "Question 898631: Divide 140 into three parts such that the second is fifteen less than the first and the third exceeds twice the first by thirty five \n" ); document.write( "
Algebra.Com's Answer #544969 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! f + (f-15) + (2f+35) = 140 (f representing the first part) \n" ); document.write( " 4f = 120 \n" ); document.write( " f = 30 \n" ); document.write( "30, 15, 95 are the three parts \n" ); document.write( " |