document.write( "Question 898678: two high sped cars leave at the same time from a city to the same island. the first car travels at 34 mph. the second car travels at 24 mph. in how many hours will the two cars be 30 miles apart? \n" ); document.write( "

Algebra.Com's Answer #544953 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+d+\"$ = distance faster car travels in miles
\n" ); document.write( " $\"+d+-+30+\"$ = distance slower car travels in miles
\n" ); document.write( "Let $\"+t+\"$ = time in hours for the cars to be 30 mi apart
\n" ); document.write( "--------------------
\n" ); document.write( "Faster car:
\n" ); document.write( " $\"+d+=+34t+\"$
\n" ); document.write( "Slower car:
\n" ); document.write( " $\"+d+-+30+=+24t+\"$
\n" ); document.write( " $\"+d+=+24t+%2B+30+\"$
\n" ); document.write( "-------------------
\n" ); document.write( "By substitution:
\n" ); document.write( " $\"+34t+=+24t+%2B+30+\"$
\n" ); document.write( " $\"+10t+=+30+\"$
\n" ); document.write( " $\"+t+=+3+\"$
\n" ); document.write( "They will be 30 mi apart in 3 hrs
\n" ); document.write( "check:
\n" ); document.write( " $\"+d+=+34t+\"$
\n" ); document.write( " $\"+d+=+34%2A3+\"$
\n" ); document.write( " $\"+d+=+102+\"$ mi
\n" ); document.write( "and
\n" ); document.write( " $\"+d+=+24t+%2B+30+\"$
\n" ); document.write( " $\"+d+=+24%2A3+%2B+30+\"$
\n" ); document.write( " $\"+d+=+72+%2B+30+\"$
\n" ); document.write( " $\"+d+=+102+\"$ mi\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

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