document.write( "Question 75926: The sides of a parallelogram have lengths 8 inches and 16 inches and one of the angles of the parallelogram has a measure of 45 degrees. Find the area of the parallelogram? \n" ); document.write( "
Algebra.Com's Answer #54495 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! THE ENDS OF THE PARALLELOGRAM FORM A RIGHT ISOSOLESE TRIANGLE WITH SIDES X, X & 8. 8 BEING THE HYPOTENUSE. WE NEED TO FIND THE OTHER SIDE FOR THE HEIGHT OF THE PARALLELOGRAM THUS: \n" ); document.write( "X^2+X^2=8^2 \n" ); document.write( "2X^2=64 \n" ); document.write( "X^2=64/2 \n" ); document.write( "X^2=32 \n" ); document.write( "X=5.65685 THIS IS THE OTHER TWO SIDES & THE HEIGHT OF THE PARALLELOGRAM. \n" ); document.write( "NOW WE MULTIPLY THE BASE TIMES THE HEIGHT. \n" ); document.write( "16*5.65685=90.51 IN^2 \n" ); document.write( " |