document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=898660>Question 898660</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You draw two slips of paper from a hat containing five slips, marked 1 through 5, with replacement.  What is the probability that exactly one of the numbers is a five?\r<BR>\n" );
document.write( "\n" );
document.write( "The following is my thought process: So for the first slip of paper, the chance of getting a 5 would be 1/5. Since the slip of paper can be replaced, the chance of getting another 5 would still be 1/5.  But since you only want one 5, would the answer be 1/10? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #544943 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=544943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P(A or B) = P(A) + P(B) - P(A and B) = 1/5 + 1/5 - (1/5)(1/5) = 2/5 - 1/25 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );