document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=898537>Question 898537</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the measure of two supplementary angles if the difference in the measures of the two angles is 32 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #544917 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=544917\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> find the measure of two supplementary angles if the difference in the measures of the two angles is 32<BR>\n" );
document.write( "let x=one of the two supplementary angles<BR>\n" );
document.write( "let y=other supplementary angle\r<BR>\n" );
document.write( "\n" );
document.write( "..<BR>\n" );
document.write( "x-y=32<BR>\n" );
document.write( "x+y=180<BR>\n" );
document.write( "add<BR>\n" );
document.write( "2x=212<BR>\n" );
document.write( "x=106<BR>\n" );
document.write( "y=180-x<BR>\n" );
document.write( "y=74<BR>\n" );
document.write( "supplementary angles are 106&#730; and 74&#730; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );