document.write( "Question 898420: Wilma drove at an average speed of 40 mi/h from her home in City A to visit her sister in City B. She stayed in City B 10 hours, and on the trip back averaged 35 mi/h. She returned home 40 hours after leaving. How many miles is City A from City B.
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document.write( "The solution cannot be calculated using the formula that already exists to find distances using time and speed.
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Algebra.Com's Answer #544844 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! Wilma had \n" ); document.write( "hours of driving time \n" ); document.write( "Let \n" ); document.write( "drive from A to B \n" ); document.write( " \n" ); document.write( "drive from B to A \n" ); document.write( "Let \n" ); document.write( "------------------------------------- \n" ); document.write( "Equation for A to B: \n" ); document.write( " \n" ); document.write( "Equation for B to A \n" ); document.write( " \n" ); document.write( "--------------------- \n" ); document.write( "By substitution: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "and \n" ); document.write( " \n" ); document.write( "----------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------------- \n" ); document.write( "City A is 560 miles from City B \n" ); document.write( "----------------- \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "OK\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |