document.write( "Question 898396: i cant figure out how to put this in a algebra equation. \"At 1:30p.m., Tom leaves in his boat from a dock and heads south. He travels at a rate of 25 miles per hour. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If she travels at a rate of 30 miles per hour, when will she catch up to Tom? \n" ); document.write( "
Algebra.Com's Answer #544826 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! 25(x+10/60)=30x \n" ); document.write( "25x+10/60*25=30x \n" ); document.write( "250/60=5x \n" ); document.write( "50/60=x \n" ); document.write( "add 50 minutes to 1:40 pm \n" ); document.write( "1:90 pm=2:30 pm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |