document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=898387>Question 898387</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the equation. Use a calculator to obtain decimal approximations, correct to two decimal places.\r<BR>\n" );
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document.write( "ln (2x+3)+ln(x-6)-2lnx = 0\r<BR>\n" );
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document.write( "I know the answer is 10.68 but im just not sure how my teacher got it. Any help would be appreciated. Thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #544808 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=544808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> ln (2x+3)+ln(x-6)-2lnx = 0 <BR>\n" );
document.write( "I know the answer is 10.68 <BR>\n" );
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document.write( "Log Law:: log(A)+log(B) = log(AB)<BR>\n" );
document.write( "Log Law:: log(A)-log(B) = log(A/B)<BR>\n" );
document.write( "Log Law: log(A^n) = n*log(A)<BR>\n" );
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document.write( "Your problem::<BR>\n" );
document.write( "ln[(2x+3)(x-6)/x^2] = 0<BR>\n" );
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document.write( "(2x+3)(x-6)/x^2 = 1<BR>\n" );
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document.write( "2x^2 +3x-12x-18 = x^2<BR>\n" );
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document.write( "x^2 -9x - 18 = 0<BR>\n" );
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document.write( "Use the Quadratic Formula to get:<BR>\n" );
document.write( "x = [9 +- sqrt(81-4*1*-18)]/2<BR>\n" );
document.write( "x = [9 +- sqrt(153)]/2<BR>\n" );
document.write( "x = [9 +- 12.37]/2<BR>\n" );
document.write( "Positive solution::<BR>\n" );
document.write( "x = 10.68 <BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
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