document.write( "Question 898178: the length of rectangular lot is three times its width.If the length is increased by 5 feet and the width is decreased by 2 feet, the area of the lot is decreased by 21 square feet. Find the dimension. \n" ); document.write( "
Algebra.Com's Answer #544792 by josgarithmetic(39617)\"\" \"About 
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w and L for dimensions.
\n" ); document.write( "Original lot, \"L=3w\", meaning A for area is \"A=wL=3w%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "Rectangle of specified new dimensions,
\n" ); document.write( "L+5 and w-2;
\n" ); document.write( "The area is \"%28L%2B5%29%28w-2%29=wL%2B5w-2L-10\"\r
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\n" ); document.write( "\n" ); document.write( "Description indicates \"wL%3EwL%2B5w-2L-10\"
\n" ); document.write( "AND
\n" ); document.write( "\"highlight_green%28wL-%28wL%2B5w-2L-10%29=21%29\"\r
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\n" ); document.write( "\n" ); document.write( "STEPS TO SOLVE
\n" ); document.write( "\"wL-wL-5w%2B2L%2B10=21\"
\n" ); document.write( "\"2L-5w%2B10=21\"
\n" ); document.write( "\"2L-5w=11\"
\n" ); document.write( "substitute according to given L versus w
\n" ); document.write( "\"2%2A3w-5w=11\"
\n" ); document.write( "\"6w-5w=11\"
\n" ); document.write( "\"highlight%28w=11%29\"\r
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\n" ); document.write( "\n" ); document.write( "Get the value of L from that:
\n" ); document.write( "\"L=3%2Aw\"
\n" ); document.write( "\"L=3%2A11\"
\n" ); document.write( "\"highlight%28L=33%29\"\r
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\n" ); document.write( "\n" ); document.write( "Original rectangle is dimensions L=33 and w=11.
\n" ); document.write( "You can evaluate dimensions of the newer rectangle if desired.
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