document.write( "Question 898178: the length of rectangular lot is three times its width.If the length is increased by 5 feet and the width is decreased by 2 feet, the area of the lot is decreased by 21 square feet. Find the dimension. \n" ); document.write( "
Algebra.Com's Answer #544792 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! w and L for dimensions. \n" ); document.write( "Original lot, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rectangle of specified new dimensions, \n" ); document.write( "L+5 and w-2; \n" ); document.write( "The area is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Description indicates \n" ); document.write( "AND \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "STEPS TO SOLVE \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "substitute according to given L versus w \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Get the value of L from that: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Original rectangle is dimensions L=33 and w=11. \n" ); document.write( "You can evaluate dimensions of the newer rectangle if desired. \n" ); document.write( " \n" ); document.write( " |