document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=898281>Question 898281</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 10:30am two planes leave Houston, one flying east at 560 km/h and the other west at 640 km/h. At what time will they be 2100 km apart?\r<BR>\n" );
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document.write( "I'm not sure what formula to put this in to solve it. I believe the answer is 1 hr 45 min travel time so it would be 12:15pm. I know RxT=D, but how do I incorporate these in that formula. I'm confused.\r<BR>\n" );
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document.write( "I drew a picture and added the 2 rates together, so in 1 hr they are 1200 km apart. Then I added 30 min, so half of 1200 is 600 which would equal 1800 km. Then I added 15 min which would be half of 600 is 300. So 1200(1 hr) + 600(30 min) + 300(15 min) = 2100 km (1 hr 45 min). 10:30am + 1 hr 45min= 12:15pm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #544786 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=544786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> both are flying in opposite directions in a straight line\r<BR>\n" );
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document.write( "so the effective speed between them is 560 +640 km/h\r<BR>\n" );
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document.write( "= 1200 km/h\r<BR>\n" );
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document.write( "rate = 1200<BR>\n" );
document.write( "d= 2100<BR>\n" );
document.write( "time taken to be 2100 apart\r<BR>\n" );
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document.write( "2100/1200<BR>\n" );
document.write( "= 1.75 hours\r<BR>\n" );
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document.write( "= 1hour 45 minutes </SPAN>\n" );
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