document.write( "Question 75883This question is from textbook Beginning Algebra
\n" ); document.write( ": Please help, I am having difficulty trying to figure Quadratic Equations. On page #575 of Begining Algebra Questions 2, 4, 6 and 14 are the ones I need help with. I need to write them in standard form and determine the values of a,b, and c. Your help is very appreciated. Thanks!! =)
\n" ); document.write( "#2. x^2+6x-5=0
\n" ); document.write( "#4. 4x^2+20x=0
\n" ); document.write( "#6. 3x^2+10x+8= -17x-2
\n" ); document.write( "#14. x^2+3x-40=0\r
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Algebra.Com's Answer #54477 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
IF YOU JUST WANT THE VALUES OF (A)X^2+(B)X+(C) THEN YOU ALREADY HAVE THEM.
\n" ); document.write( "2) X^2+6X-5=0 HERE YOU HAVE A=1, B=6 & C=-5
\n" ); document.write( "IF YOU NEED TO FIND THE TWO TERMS OR X THEN YOU NEED TO USE IN THIS CASE THE QUADRATIC EQUATION:
\n" ); document.write( "X=(-6+-SQRT[6^6-4*1*-5])/2*1
\n" ); document.write( "X=(-6+-SQRT[36+20])/2
\n" ); document.write( "X=(-6+-SQRT56)/2
\n" ); document.write( "X=(-6+-7.48)/2
\n" ); document.write( "X=(-6+7.48)/2
\n" ); document.write( "X=1.48/2
\n" ); document.write( "X=.74 ANSWER
\n" ); document.write( "X=(-6-7.48)/2
\n" ); document.write( "X=-13.48/2
\n" ); document.write( "X=--6.74 ANSWER.
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