document.write( "Question 898334: If one angle is 3 times the measure of angle 2, and the third angle is 5 times the measure of angle 2 subtracted by 90, then find the measure of all three angles. \r
\n" ); document.write( "\n" ); document.write( "I have been stumped on this problem for ever. I know they all equal 180, but i can't find the measure of angle 2 and when I do when i plug in the formula it ends up being more than 180.
\n" ); document.write( "Please help.
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Algebra.Com's Answer #544758 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+alpha+\" = angle 2
\n" ); document.write( "\"+3%2Aalpha+\" = angle 1
\n" ); document.write( "\"+5%2Aalpha+-+90+\" = angle 3
\n" ); document.write( "----------------------------
\n" ); document.write( "Do you mean the 3 angles add up to 180 degrees?
\n" ); document.write( "If so,
\n" ); document.write( "\"+alpha+%2B+3%2Aalpha+%2B+5%2Aalpha+-+90+=+180+\"
\n" ); document.write( "\"+9%2Aalpha+-+90+=+180+\"
\n" ); document.write( "\"+9%2Aalpha+=+270+\"
\n" ); document.write( "\"+alpha+=+30+\"
\n" ); document.write( "-------------------
\n" ); document.write( "Angle 2 = 30 degrees
\n" ); document.write( "----------------------
\n" ); document.write( "Angle 1 = \"+3%2A30+\"
\n" ); document.write( "Angle 1 = 90 degrees
\n" ); document.write( "----------------------
\n" ); document.write( "Angle 3 = \"+5%2A30+-+90+\"
\n" ); document.write( "Angle 3 = \"+150+-+90+\"
\n" ); document.write( "Angle 3 = 60 degrees
\n" ); document.write( "----------------------
\n" ); document.write( "check:
\n" ); document.write( "\"+30+%2B+90+%2B+60+=+180+\" degrees
\n" ); document.write( "OK\r
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