document.write( "Question 885491: James needs to mix a 10% saline solution with a 50% saline solution to create 200 mL of a 18% solution. How many mL of each solution must James use? \n" ); document.write( "
Algebra.Com's Answer #544725 by richwmiller(17219)![]() ![]() You can put this solution on YOUR website! a+b=200, \n" ); document.write( "0.1*a+0.5*b=0.18*200 \n" ); document.write( "a=200-b \n" ); document.write( "0.1*(200-b)+0.5*b=36 \n" ); document.write( "20-0.1b+0.5*b=36 \n" ); document.write( "0.4*b=16 \n" ); document.write( "b=40 \n" ); document.write( "a=200-b \n" ); document.write( "a=160 b=40 \n" ); document.write( " \n" ); document.write( " |