document.write( "Question 10300: Mary bought some donuts. She gave 1/2 her donuts and 1/2 a donut to her mom. Then she gave away 1/2 her remaining donuts and 1/2 a donut to her aunt. Then she gave 1/2 of her remaining donuts and 1/2 a donut to her sister, Kathy. This left her with 1/4 of a dozen donuts. How many doughnuts had she bought?\r
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Algebra.Com's Answer #5446 by rapaljer(4671)![]() ![]() You can put this solution on YOUR website! Let's work this one backwards:\r \n" ); document.write( "\n" ); document.write( "Mary ends up with 3 donuts after giving half of them and a half a donut to her sister Kathy. This means that before giving donuts to her sister Kathy, Mary must have had 7 donuts (of the 7 donuts, she gave half of them--3 1/2--plus a half, which would be 4 donuts to her sister, leaving her with 3 donuts for herself!)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, this means that she ended up with 7 donuts after giving half of them plus a half donut to her aunt. By the same thinking, she must have had 15 donuts before giving 8 donuts to her aunt (7 1/2 + 1/2), leaving 7 for herself.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, if she ended up with 15 donuts after giving half plus a half a donut to her mother, she must have started out with 31 donuts.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now check it by seeing if it works:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Mary started with 31 donuts (half would be 15 1/2, + 1/2 means that she gave 16 to her mother), which leaves her with 15. She gave 7 1/2 + 1/2 or 8 to her aunt, leaving her with 7 donuts. She gave 3 1/2 + 1/2 or 4 to her sister, leavning her with 3 donuts or 1/4 of a dozen. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Do you think there is a math formula for this? Did you notice that at each step of the problem, each time she had donuts left, it was 1 less than a power of 2? She started with 31 ( 32 -1), went down to 15 (16-1), then to 7 (8-1), and 3 (4-1). Interesting problem. Probably some high powered math here!!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC \n" ); document.write( " |