document.write( "Question 898049: logx+log(x-5)=1 \n" ); document.write( "

Algebra.Com's Answer #544574 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"log%28%28x%29%29%2Blog%28%28x-5%29%29=1\"$
\n" ); document.write( " $\"log%28%28x%28x-5%29%29%29=1\"$
\n" ); document.write( " $\"x%28x-5%29=10\"$
\n" ); document.write( " $\"x%5E2-5x=10\"$
\n" ); document.write( " $\"x%5E2-5x%2B25%2F4=10%2B25%2F4\"$
\n" ); document.write( " $\"%28x-5%2F2%29%5E2=40%2F4%2B25%2F4\"$
\n" ); document.write( " $\"%28x-5%2F2%29%5E2=65%2F4\"$
\n" ); document.write( " $\"x-5%2F2=0+%2B-+sqrt%2865%29%2F2\"$
\n" ); document.write( " $\"x=5%2F2+%2B-+sqrt%2865%29%2F2\"$
\n" ); document.write( "Since only positive log arguments are allowed.
\n" ); document.write( " $\"x=5%2F2+%2B+sqrt%2865%29%2F2\"$
\n" ); document.write( " \n" ); document.write( "

\n" );