document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=898146>Question 898146</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If you have a standard deck of cards how many ways can you deal out <BR>\n" );
document.write( "a) 5 cards    b) 5 red cards\r<BR>\n" );
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document.write( "I think this a a combination problem - I did this <BR>\n" );
document.write( "a) C(52,5)   b) C(26,5) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #544567 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=544567\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> i originally thought combinatios was the correct way to go, but i now lean toward permutations.\r<BR>\n" );
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document.write( "the key is how many ways can you deal them out, rather than how many possible sets of 5 cards can you get,\r<BR>\n" );
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document.write( "you can get C(5,2) possible 5 card sets.  this is true because set is unique regardless of the order the order in which the cards are arranged.\r<BR>\n" );
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document.write( "if you then want to deal these out, you can deal each of those 5 card sets out in 5! ways.\r<BR>\n" );
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document.write( "since C(52,5) * 5! is equal to P(52,5), then permutations would be a more suitable answer.\r<BR>\n" );
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document.write( "i will go with permutations.\r<BR>\n" );
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document.write( "this is in agreement with what the other tutor told you.\r<BR>\n" );
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document.write( "it makes more sense now that i had a chance to look at it again.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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