Algebra.Com's Answer #544542 by MathTherapy(10552)  You can put this solution on YOUR website! The length and the width of a rectangular floor a m and b m. Solve for a and b, given the following \n" );
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document.write( " If the length and the width each increases with 1 m, the area will increase with 9 m^2. \n" );
document.write( " If the length decreases with 0.5 m and the width increases with 4 m, the area is doubled. \n" );
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document.write( "Length: a \n" );
document.write( "Width: b \n" );
document.write( "Area: ab\r \n" );
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document.write( "An increase in length, by 1 results in new length being: a + 1 \n" );
document.write( "An increase in width, by 1 results in new width being: b + 1 \n" );
document.write( "If new area increases by 9, then: (a + 1)(b + 1) = ab + 9 \n" );
document.write( "ab + a + b + 1 = ab + 9 \n" );
document.write( "ab - ab + a + b = 9 - 1 \n" );
document.write( "a + b = 8____a = 8 - b ------ eq (i)\r \n" );
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document.write( "A decrease in length, by .5 results in new length being: a - .5 \n" );
document.write( "An increase in width, by 4 results in new width being: b + 4 \n" );
document.write( "If new area is doubled, then new area becomes: 2ab \n" );
document.write( "Therefore, (a - .5)(b + 4) = 2ab \n" );
document.write( "ab + 4a - .5b - 2 = 2ab \n" );
document.write( "2ab - ab - 4a + .5b = - 2 \n" );
document.write( "ab - 4a + .5b = - 2 ------- eq (ii)\r \n" );
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document.write( "b(8 - b) - 4(8 - b) + .5b = - 2 ------ Substituting 8 - b for a on eq (ii) \n" );
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document.write( " ------- Multiplying by 2 to clear decimal \n" );
document.write( "Using the quadratic equation, \n" );
document.write( "width, or OR (ignore as a = 8 - b, which would result in a negative value for a) \n" );
document.write( "a = 8 - 3.2396 ------- Substituting 3.2396 for b in eq (i) \n" );
document.write( "Length, or  \n" );
document.write( "You can do the check!! \r \n" );
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document.write( "Send comments, thank-yous, and inquiries to D at MathMadEzy@aol.com. \n" );
document.write( "Further help is available, online or in-person, for a fee, obviously. \r \n" );
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