document.write( "Question 897869: Find the volume of ice cream in the cone [picture of cone with 6-cm. diameter opening and 11-cm. height] if the entire cone is filled. (The dome on the top is half of a sphere.) Round your answer to the hundredths place. \r
\n" ); document.write( "\n" ); document.write( "I found the numeric answer the answer key gave (160.14), but not the cm. cubed that is part of the answer. I used the formulas for a cone [V=1/3(3.14)(r squared)(h)] and a sphere [V=4/3(3.14)(r cubed)] and added the results (minus half the sphere), but I didn't think you could add cm. squared and cm. cubed together.
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Algebra.Com's Answer #544506 by KMST(5328)\"\" \"About 
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You are using lengths in cm to calculate volumes in cubic centimeters.
\n" ); document.write( "Then, you are adding two volumes in cubic centimeters to get a total volume in cubic centimeters.
\n" ); document.write( "When you calculate \"V=%281%2F3%29%283.14%29%28r%5E2%29%28h%29\" for the volume of the cone,
\n" ); document.write( "\"r\" and \"h\" are in cm,
\n" ); document.write( "and you are multiplying 3 measurements in cm,
\n" ); document.write( "so \"%28r%5E2%29%28h%29=%28r%29%28r%29%28h%29\" and \"V=%281%2F3%29%283.14%29%28r%5E2%29%28h%29\" come out in \"cm%5E3\" (cubic centimeters).
\n" ); document.write( "For the volume of the half sphere, \"r%5E3=%28e%29%28r%29%28r%29\" is also in \"cm%5E3\" .
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