document.write( "Question 897954: Rapheal paid $1,148 for a camera during a 30% off sale. What was the cameras regular price.\r
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Algebra.Com's Answer #544467 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! x = original price\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "30% of x = 0.30x (this is the amount you save, aka the discount)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x - 0.30x = 0.70x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So the final price is 0.70x, or 70% of the original price\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.70x = 1148\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.70x/0.70 = 1148/0.70\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 1640\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The camera's original price is $1,640 (this is before the discount is applied) \n" ); document.write( " |