document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=897886>Question 897886</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 10 liters of a 50% salt solution. all she has available is a 20% salt solution and a 70% salt solution. how much of each of the two solutions should she mix to obtain her desired solution? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #544409 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=544409\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A chemist needs 10 liters of a 50% salt solution. all she has available is a 20% salt solution and a 70% salt solution. how much of each of the two solutions should she mix to obtain her desired solution?<BR>\n" );
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document.write( "Let x = amount (liters) of 70%<BR>\n" );
document.write( "then<BR>\n" );
document.write( "10-x = amount (liters) of 20%<BR>\n" );
document.write( ".<BR>\n" );
document.write( ".70x + .20(10-x) = .50(10)<BR>\n" );
document.write( ".70x + 2-.20x = 5<BR>\n" );
document.write( ".50x + 2 = 5<BR>\n" );
document.write( ".50x = 3<BR>\n" );
document.write( "x = 6 liters (70%)<BR>\n" );
document.write( ".<BR>\n" );
document.write( "amount of 20%:<BR>\n" );
document.write( "10-x = 10-6 = 4 liters<BR>\n" );
document.write( " </SPAN>\n" );
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