document.write( "Question 75787This question is from textbook algebra I
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\n" ); document.write( "\n" ); document.write( " |8-(w-1)|≤9 \n" ); document.write( "
Algebra.Com's Answer #54436 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "Solve the open sentence and graph the solution set. \r\n" );
document.write( "|8-(w-1)| £ 9\r\n" );
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document.write( "Rules for removing absolute values in inequalities:\r\n" );
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document.write( "1.   |EXPRESSION| < A , where A is positive\r\n" );
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document.write( "is equivalent to:\r\n" );
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document.write( "    -A < EXPRESSION < A\r\n" );
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document.write( "2.   |EXPRESSION| > A , where A is positive\r\n" );
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document.write( "is equivalent to:\r\n" );
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document.write( "EXPRESSION < -A  OR  EXPRESSION > A \r\n" );
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document.write( "Rule 1 is the same for £\r\n" );
document.write( "as for < and rule 2 is the same for ³ as for >.\r\n" );
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document.write( "|8-(w-1)| £ 9\r\n" );
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document.write( "Rule 1 applies, so\r\n" );
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document.write( "-9 £ 8-(w-1) £ 9\r\n" );
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document.write( " -9 £ 8-w+1 £ 9\r\n" );
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document.write( "  -9 £ 9-w £ 9\r\n" );
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document.write( "Add -9 to all three sides:\r\n" );
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document.write( "  -9-9 £ 9-w-9 £ 9-9\r\n" );
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document.write( "    -18 £ -w £ 0\r\n" );
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document.write( "Divide through by -1, which\r\n" );
document.write( "reverses the inequality symbols:\r\n" );
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document.write( "     18 ³ w ³ 0\r\n" );
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document.write( "This can be written as\r\n" );
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document.write( "     0 £ w £ 18\r\n" );
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document.write( "The graph is\r\n" );
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document.write( "-------·=====================================================·------\r\n" );
document.write( "-2 -1  0  1  2  3  4  5  6  7  8  9 10 11 12 13 14 15 16 17 18 19 20    \r\n" );
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document.write( "which in interval notation is [0, 18]\r\n" );
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document.write( "Edwin
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