document.write( "Question 897660: Hi. I have 3 problems that I am having difficulty with and I was wondering if you could help.\r
\n" ); document.write( "\n" ); document.write( "1) 4x^2 = 12x\r
\n" ); document.write( "\n" ); document.write( "2) 6x^2 = 6x\r
\n" ); document.write( "\n" ); document.write( "3) 3x^2 + 6 = 2x^2 +18\r
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\n" ); document.write( "\n" ); document.write( "Thanks!
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Algebra.Com's Answer #544266 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
(1)
\n" ); document.write( "\"+4x%5E2+=+12x+\"
\n" ); document.write( "\"+4x%5E2+-+12x+=+0+\"
\n" ); document.write( "\"+4x%2A%28+x+-+3+%29+=+0+\"
\n" ); document.write( "For this to be true, either
\n" ); document.write( "\"+x+=+0+\" or \"+x+=+3+\"
\n" ); document.write( "----------------------
\n" ); document.write( "(2)
\n" ); document.write( "\"+6x%5E2+=+6x+\"
\n" ); document.write( "\"+6x%5E2+-+6x+=+0+\"
\n" ); document.write( "\"+6x%2A%28+x+-+1+%29+=+0+\"
\n" ); document.write( "\"+x+=+0+\" and
\n" ); document.write( "\"+x+=+1+\"
\n" ); document.write( "--------------
\n" ); document.write( "(3)
\n" ); document.write( "\"+3x%5E2+%2B+6+=+2x%5E2+%2B+18+\"
\n" ); document.write( "Subtract \"+2x%5E2+\" from both sides
\n" ); document.write( "\"+x%5E2+%2B+6+=+18+\"
\n" ); document.write( "Subtract \"+6+\" from both sides
\n" ); document.write( "\"+x%5E2+=+12+\"
\n" ); document.write( "\"+x+=+sqrt%2812%29+\"
\n" ); document.write( "\"+x+=+2%2Asqrt%283%29+\"
\n" ); document.write( "and, also
\n" ); document.write( "\"+x+=+-sqrt%2812%29+\"
\n" ); document.write( "\"+x+=+-2%2Asqrt%283%29+\"
\n" ); document.write( "
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