document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=897721>Question 897721</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A large grain silo is to be constructed in the shape of a circular cylinder with a hemisphere attached to the top. The diameter of the silo is to be 30 feet, but the height is yet to be determined. Find the height h of the silo that will result in a capacity of 11,925&#960; ft3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #544257 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39617)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=544257\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The radius is half the diameter, so r=15 feet.\r<BR>\n" );
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document.write( "Let h = tallness of only the straight cylinder portion.  The whole silo tallness will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight_green%28h%2Br%29 ALIGN=MIDDLE  ALT=\"highlight_green%28h%2Br%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >.  Your question is unclear, but you want a final result of either h or h+r.\r<BR>\n" );
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document.write( "Volume of the silo, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%2Api%2Ar%5E2%2B%281%2F2%29%284%2F3%29pi%2Ar%5E3=11925pi ALIGN=MIDDLE  ALT=\"h%2Api%2Ar%5E2%2B%281%2F2%29%284%2F3%29pi%2Ar%5E3=11925pi\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%2Api%2Ar%5E2%2B%282%2F3%29pi%2Ar%5E3=11925pi ALIGN=MIDDLE  ALT=\"h%2Api%2Ar%5E2%2B%282%2F3%29pi%2Ar%5E3=11925pi\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%2Ar%5E2%2B%282%2F3%29r%5E3=11925 ALIGN=MIDDLE  ALT=\"h%2Ar%5E2%2B%282%2F3%29r%5E3=11925\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=hr%5E2=11925-%282%2F3%29r%5E3 ALIGN=MIDDLE  ALT=\"hr%5E2=11925-%282%2F3%29r%5E3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=11925%2Fr%5E2-%282%2F3%29%28r%5E3%29%2Fr%5E2 ALIGN=MIDDLE  ALT=\"h=11925%2Fr%5E2-%282%2F3%29%28r%5E3%29%2Fr%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=11925%2F225-%282%2F3%29r ALIGN=MIDDLE  ALT=\"h=11925%2F225-%282%2F3%29r\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=11925%2F225-2%2A15%2F3 ALIGN=MIDDLE  ALT=\"h=11925%2F225-2%2A15%2F3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h=11925%2F225-10=53-10 ALIGN=MIDDLE  ALT=\"h=11925%2F225-10=53-10\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=highlight%28h=43%29 ALIGN=MIDDLE  ALT=\"highlight%28h=43%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > feet, just the straight cylinder part.\r<BR>\n" );
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document.write( "The whole silo from top to bottom is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=43%2B15=58 ALIGN=MIDDLE  ALT=\"43%2B15=58\"   DISABLED_style= \"max-width:90%; height:auto;\" > feet.<BR>\n" );
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