document.write( "Question 897722: To start a mobile dog-grooming service, a woman borrowed $2000. If the loan was for 2 years and the amount of interest was $124, what simple interest rate was she charged? \n" ); document.write( "
Algebra.Com's Answer #544255 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Simple Interest\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Interest = Principal*Rate*Time\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I = P*r*t\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "124 = 2000*r*2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "124 = 2000*2*r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "124 = 4000*r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "124/4000 = r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "0.031 = r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "r = 0.031\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Convert 0.031 to a percentage: 0.031*100 = 3.1%\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The simple interest rate is 3.1% \n" ); document.write( " |