document.write( "Question 897709: how can i show work on this question?
\n" ); document.write( "5/x+2/5=7/x
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Algebra.Com's Answer #544248 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Here is one way to solve for x. First I combined the fractions on the left side (by getting the LCD first). From there I cross multiplied and then isolated x.\r
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\n" ); document.write( "\n" ); document.write( "\"5%2Fx%2B2%2F5=7%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"%285%2A5%29%2F%285%2Ax%29%2B2%2F5=7%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"25%2F%285x%29%2B2%2F5=7%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"25%2F%285x%29%2B%28x%2A2%29%2F%28x%2A5%29=7%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"25%2F%285x%29%2B%282x%29%2F%285x%29=7%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2825%2B2x%29%2F%285x%29=7%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "\"%2825%2B2x%29%2Ax=5x%2A7\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2825%2B2x%29=5x%2A7\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2825%29%2Bx%282x%29=5x%2A7\"\r
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\n" ); document.write( "\n" ); document.write( "\"25x%2B2x%5E2=35x\"\r
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\n" ); document.write( "\n" ); document.write( "\"25x%2B2x%5E2-35x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2B25x-35x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2-10x=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x%28x-5%29=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"2x=0\" or \"x-5=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0%2F2\" or \"x-5=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x-5=0\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x=0%2B5\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=0\" or \"x=5\"\r
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\n" ); document.write( "\n" ); document.write( "The two *possible* solutions are \"x=0\" or \"x=5\"\r
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\n" ); document.write( "\n" ); document.write( "However, only \"x=5\" works because plugging \"x=0\" back into the original equation gives you a division by zero error. \r
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\n" ); document.write( "\n" ); document.write( "So the final answer is \"x+=+5\"
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