document.write( "Question 75793: please see if this problem is correct and thanks in advance \r
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document.write( "Factor completely: 3x^2+12x+12
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document.write( "3x^2+(2^2 3)x+2^2.3
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document.write( "3[(x+2)^2]
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document.write( "3(x+2^2)\r
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document.write( "Thanks a millon \n" );
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Algebra.Com's Answer #54421 by bucky(2189)![]() ![]() ![]() You can put this solution on YOUR website! Factor completely: \n" ); document.write( ". \n" ); document.write( "3x^2+12x+12 \n" ); document.write( ". \n" ); document.write( "3x^2+(2^2*3)x+2^2*3 <--- this is correct. But you might have found it easier \n" ); document.write( "to just look at the coefficients of the terms in the original polynomial and \n" ); document.write( "recognize that they were all divisible by 3. Then you could have factored out \n" ); document.write( "the 3 to get 3(x^2 + 4x + 4) \n" ); document.write( ". \n" ); document.write( "3[(x+2)^2] <--- this is correct \n" ); document.write( ". \n" ); document.write( "3(x+2^2) <--- this is not correct. 2^2 is 4 and therefore what you have in \n" ); document.write( "the parentheses is x + 4. I'm pretty sure that all that you meant to do \n" ); document.write( "was to delete the brackets leaving just the answer as: \n" ); document.write( ". \n" ); document.write( "3(x + 2)^2 <--- and this is correct \n" ); document.write( ". \n" ); document.write( "With the exception of this minor error, you went about the problem correctly. You seem \n" ); document.write( "to have the process down correctly. Good work!\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |