document.write( "Question 897477: Find the equation of a rational function which has an oblique asymptote at y=2x+1, a vertical asymptote at x= -1, and a hole at (3,0). Thanks! \n" ); document.write( "

Algebra.Com's Answer #544151 by josgarithmetic(39620) $\"\"$ $\"About$

You can put this solution on YOUR website!
Something like $\"a%28%28x%5E2-something%29%28x-3%29%29%2F%28%28x%2B1%29%28x-3%29%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "and you want to be able to perform a division (after simplification) that makes a quotient of 2x+1 and have a remainder of denominator of x+1.\r
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\n" ); document.write( "\n" ); document.write( "The simplification would be to cancel the (x-3) so you have something of $\"a%28x%5E2%2B-+something%29%2F%28x%2B1%29\"$ ; you could ignore the factor \"a\" in doing the division. Dividend would be some variable $\"x%5E2%2Bmx%2Bn\"$ , divisor is $\"x%2B1\"$ , and you know that remainder will be some $\"numerator%2F%28x%2B1%29\"$ ; The quotient as said, must be 2x+1. \n" ); document.write( "

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