document.write( "Question 897380: a right angled triangle has a perimeter of 40 and an area of 60,what are the lengths of the sides \n" ); document.write( "
Algebra.Com's Answer #544130 by Fombitz(32388)\"\" \"About 
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Let the sides be x and y.
\n" ); document.write( "For area,
\n" ); document.write( "\"A=%281%2F2%29xy=60\"
\n" ); document.write( "\"xy=120\"
\n" ); document.write( "For perimeter,
\n" ); document.write( "\"P=x%2By%2Bsqrt%28x%5E2%2By%5E2%29\"
\n" ); document.write( "\"x%2By%2Bsqrt%28x%5E2%2By%5E2%29=40\"
\n" ); document.write( "From area,
\n" ); document.write( "\"y=120%2Fx\"
\n" ); document.write( "Substitute,
\n" ); document.write( "\"x%2By%2Bsqrt%28x%5E2%2By%5E2%29=40\"
\n" ); document.write( "\"x%2B120%2Fx%2Bsqrt%28x%5E2%2B14400%2Fx%5E2%29=40\"
\n" ); document.write( "\"x%2B120%2Fx%2Bsqrt%28x%5E4%2Fx%5E2%2B14400%2Fx%5E2%29=40\"
\n" ); document.write( "\"x%2B120%2Fx%2Bsqrt%28%28x%5E4%2B14400%29%2Fx%5E2%29=40\"
\n" ); document.write( "\"x%2B120%2Fx%2B%281%2Fx%29%2Asqrt%28x%5E4%2B14400%29=40\"
\n" ); document.write( "\"x%5E2%2B120%2Bsqrt%28x%5E4%2B14400%29=40x\"
\n" ); document.write( "\"sqrt%28x%5E4%2B14400%29=-x%5E2%2B40x-120\"
\n" ); document.write( "\"x%5E4%2B14400=x%5E4-80x%5E3%2B1840x%5E2-9600x%2B14400\"
\n" ); document.write( "\"-80x%5E2%2B1840x-9600=0\"
\n" ); document.write( "\"x%5E2-23x%2B120=0\"
\n" ); document.write( "\"%28x-8%29%28x-15%29=0\"
\n" ); document.write( "Two solutions:
\n" ); document.write( "\"x-8=0\"
\n" ); document.write( "\"x=8\"
\n" ); document.write( "Then,
\n" ); document.write( "\"y=120%2F8=15\"
\n" ); document.write( "and
\n" ); document.write( "\"x-15=0\"
\n" ); document.write( "\"x=15\"
\n" ); document.write( "Then,
\n" ); document.write( "\"y=120%2F15=8\"
\n" ); document.write( "The two sides are \"8\" and \"15\" and the hypotenuse is
\n" ); document.write( "\"8%2B15%2BH=40\"
\n" ); document.write( "\"H=17\"
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