document.write( "Question 897274: Lance heads directly east at a constant rate of 25 miles per hour. One hour later, Levi leaves the same spot heading directly west at a constant rate of 20 miles per hour. How long after Levi leaves will the two cyclists be 250 miles apart? \n" ); document.write( "
Algebra.Com's Answer #544085 by Theo(13342)![]() ![]() You can put this solution on YOUR website! rate * time = distance. \n" ); document.write( "r * t = d\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d = 250\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "time for Lance is T \n" ); document.write( "time for Levi is T-1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Lance travels at 25 mph. \n" ); document.write( "Levi travels at 20 mph.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the sum of their distances must be equal to 250.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "you get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "25*T + 20*(T-1) = 250\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for T to get T = 6 \n" ); document.write( "this means that T-1 = 5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the 2 cyclists will be 250 miles apart 5 hours after Levi starts.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Lance travels 6 hours at 25 miles per hour for a distance of 150 miles. \n" ); document.write( "Levi travels 5 hours at 20 miles per hour for a distance of 100 miles. \n" ); document.write( "100 + 150 = 250.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |