document.write( "Question 75717: I need some help with some algebra word problems. I can't quite figure out the answers.\r
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document.write( "If you could help me i would greatly appreciate it.\r
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document.write( "The difference between the width and the length of a field is 12 m. Find its dimensions if a fence 160 m in length encloses it.\r
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document.write( "The length of a rectangle is found by doubling thw width and subtracting 3 m. Find its dimensions if the perimeter is 84 m. \n" );
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Algebra.Com's Answer #54395 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! 2L+2W=160 & W-L=12 THUS W=L+12 \n" ); document.write( "2L+2(L+12)=160 \n" ); document.write( "2L+2L+24=160 \n" ); document.write( "4L=160-24 \n" ); document.write( "4L=136 \n" ); document.write( "L=136/4 \n" ); document.write( "L=34 M FOR THE LENGTH. \n" ); document.write( "W-34=12 \n" ); document.write( "W=12+34 \n" ); document.write( "W=46 M FOR THE WIDTH. \n" ); document.write( "PROOF \n" ); document.write( "2*34+2*46=160 \n" ); document.write( "68+92=160 \n" ); document.write( "160=160 \n" ); document.write( "------------------------------------------------ \n" ); document.write( "2W+2(2W-3)=84 \n" ); document.write( "2W+4W-6=84 \n" ); document.write( "6W=84+6 \n" ); document.write( "6W=90 \n" ); document.write( "W=90/6 \n" ); document.write( "W=15 M. FOR THE WIDTH \n" ); document.write( "L=2*15-3 \n" ); document.write( "L=30-3 \n" ); document.write( "L=27 M. FOR THE LENGTH. \n" ); document.write( "PROOF \n" ); document.write( "2*15+2*27=84 \n" ); document.write( "30+54=84 \n" ); document.write( "84=84 \n" ); document.write( " |