document.write( "Question 75717: I need some help with some algebra word problems. I can't quite figure out the answers.\r
\n" ); document.write( "\n" ); document.write( "If you could help me i would greatly appreciate it.\r
\n" ); document.write( "\n" ); document.write( "The difference between the width and the length of a field is 12 m. Find its dimensions if a fence 160 m in length encloses it.\r
\n" ); document.write( "\n" ); document.write( "The length of a rectangle is found by doubling thw width and subtracting 3 m. Find its dimensions if the perimeter is 84 m.
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Algebra.Com's Answer #54395 by checkley75(3666)\"\" \"About 
You can put this solution on YOUR website!
2L+2W=160 & W-L=12 THUS W=L+12
\n" ); document.write( "2L+2(L+12)=160
\n" ); document.write( "2L+2L+24=160
\n" ); document.write( "4L=160-24
\n" ); document.write( "4L=136
\n" ); document.write( "L=136/4
\n" ); document.write( "L=34 M FOR THE LENGTH.
\n" ); document.write( "W-34=12
\n" ); document.write( "W=12+34
\n" ); document.write( "W=46 M FOR THE WIDTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2*34+2*46=160
\n" ); document.write( "68+92=160
\n" ); document.write( "160=160
\n" ); document.write( "------------------------------------------------
\n" ); document.write( "2W+2(2W-3)=84
\n" ); document.write( "2W+4W-6=84
\n" ); document.write( "6W=84+6
\n" ); document.write( "6W=90
\n" ); document.write( "W=90/6
\n" ); document.write( "W=15 M. FOR THE WIDTH
\n" ); document.write( "L=2*15-3
\n" ); document.write( "L=30-3
\n" ); document.write( "L=27 M. FOR THE LENGTH.
\n" ); document.write( "PROOF
\n" ); document.write( "2*15+2*27=84
\n" ); document.write( "30+54=84
\n" ); document.write( "84=84
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