document.write( "Question 897021: A party of fishermen rented a boat for $240. Two of the men had to withdraw from the party and, as result, the share of each of the others was increased by $10. How many were int he original party? \n" ); document.write( "
Algebra.Com's Answer #543935 by stanbon(75887) ![]() You can put this solution on YOUR website! A party of fishermen rented a boat for $240. Two of the men had to withdraw from the party and, as result, the share of each of the others was increased by $10. How many were int he original party? \n" ); document.write( "-------- \n" ); document.write( "Let original number in party be \"x\":: \n" ); document.write( "Average cost per person = 240/x \n" ); document.write( "-------- \n" ); document.write( "New number in the party:: x-2 \n" ); document.write( "New Average cost per person:: 240/(x-2) \n" ); document.write( "------ \n" ); document.write( "Equation:: \n" ); document.write( "New average - old average = 10 dollars \n" ); document.write( "------ \n" ); document.write( "240/(x-2) - 240/x = 10 \n" ); document.write( "----- \n" ); document.write( "240x - 240(x-2) = 10x(x-2) \n" ); document.write( "-------- \n" ); document.write( "480 = 10x^2-20x \n" ); document.write( "x^2 - 2x - 48 = 0 \n" ); document.write( "x = 8 (original # in party) \n" ); document.write( "------------------------------ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |