document.write( "Question 75687: x+4/x^3-3x^2-4x+12 + 3/x^2-5x+6 = 3x/x^2-4.\r
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document.write( "This problem is not working out for me, I come up with x^2+3x+8=0 \n" );
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Algebra.Com's Answer #54391 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! I assume you mean: (a few brackets would help) \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "All the denominators will factor: \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "A common denominator is (x-2)(x+2)(x-3), multiply each term by this and you have: \n" ); document.write( ": \n" ); document.write( "(x+4) + 3(x+2) = 3x(x-3) \n" ); document.write( ": \n" ); document.write( "x + 4 + 3x + 6 = 3x^2 - 9x \n" ); document.write( ": \n" ); document.write( "4x + 10 = 3x^2 - 9x \n" ); document.write( ": \n" ); document.write( "Arrange as a quadratic equation: \n" ); document.write( "3x^2 - 9x - 4x - 10 = 0 \n" ); document.write( "3x^2 - 13x - 10 = 0 \n" ); document.write( ": \n" ); document.write( "This factors to: \n" ); document.write( "(3x + 2)(x -5) = 0 \n" ); document.write( ": \n" ); document.write( "3x = -2 \n" ); document.write( "x = -2/3 \n" ); document.write( "and \n" ); document.write( "x = +5 \n" ); document.write( ": \n" ); document.write( "I substituted 5 for x in the original equation and got equality, \n" ); document.write( "I'll let you check out the x = -2/3 solution \n" ); document.write( " \n" ); document.write( " |