document.write( "Question 896967: Solve 16^(x+3)=64^(2x-5) \n" ); document.write( "
Algebra.Com's Answer #543891 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Solve 16^(x+3)=64^(2x-5)
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document.write( "\"16%5E%28x+%2B+3%29+=+64%5E%282x+-+5%29\"
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document.write( "\"%284%5E2%29%5E%28x+%2B+3%29+=+%284%5E3%29%5E%282x+-+5%29\"
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document.write( "\"4%5E%282%28x+%2B+3%29%29+=+4%5E%283%282x+-+5%29%29\"
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document.write( "2(x + 3) = 3(2x - 5) ------ Bases are equal, and so are their exponents
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document.write( "2x + 6 = 6x - 15
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document.write( "2x - 6x = - 15 - 6
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document.write( "- 4x = - 21
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document.write( "\"x+=+%28-+21%29%2F%28-+4%29\", or \"highlight_green%28highlight_green%285.25%29%29\"
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document.write( "You can do the check!! \r
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