document.write( "Question 896951: John can finish a job two hours longer than Cris. after working for one hour,Cris joins him and complete the job in 3 more hours. how long would it take john to finish the job if he worked alone? \n" ); document.write( "
Algebra.Com's Answer #543883 by josgarithmetic(39617)\"\" \"About 
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Let x = time for Chris to do the job himself alone.\r
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\n" ); document.write( "\n" ); document.write( "Rates of Work For Each Worker:
\n" ); document.write( "John, \"1%2F%28x%2B2%29\"
\n" ); document.write( "Chris, \"1%2Fx\"\r
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\n" ); document.write( "\n" ); document.write( "RT=J for Rate, Time, Job.\r
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\n" ); document.write( "\n" ); document.write( "Account for the 1 job which John and Chris do.
\n" ); document.write( "\"highlight_green%28%281%2F%28x%2B2%29%29%2A1%2B%281%2F%28x%2B2%29%2B1%2Fx%29%2A3=1%29\".
\n" ); document.write( "This is amount of job John does in 1 hour plus amount of job both John and Crhis do together for 3 hours.
\n" ); document.write( "Solve for x and then evaluate x+2.\r
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\n" ); document.write( "\n" ); document.write( "Begin recognizing the lowest common denominator is x(x+2); and multiply the members by this, and simplify.
\n" ); document.write( "Solve ...
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