document.write( "Question 896951: John can finish a job two hours longer than Cris. after working for one hour,Cris joins him and complete the job in 3 more hours. how long would it take john to finish the job if he worked alone? \n" ); document.write( "
Algebra.Com's Answer #543883 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! Let x = time for Chris to do the job himself alone.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Rates of Work For Each Worker: \n" ); document.write( "John, \n" ); document.write( "Chris, \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "RT=J for Rate, Time, Job.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Account for the 1 job which John and Chris do. \n" ); document.write( " \n" ); document.write( "This is amount of job John does in 1 hour plus amount of job both John and Crhis do together for 3 hours. \n" ); document.write( "Solve for x and then evaluate x+2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Begin recognizing the lowest common denominator is x(x+2); and multiply the members by this, and simplify. \n" ); document.write( "Solve ... \n" ); document.write( " \n" ); document.write( " |