document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896895>Question 896895</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of the rectangular playing field is 324 yards. The length of the field is 6 yards less than double the width what are the dimesions of the playing field? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543877 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543877\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 2lengths + 2widths<BR>\n" );
document.write( "P = 324<BR>\n" );
document.write( "L = 2W-6<BR>\n" );
document.write( "Take the known value of L from the bottom equation and put it into the top.<BR>\n" );
document.write( "P = 2L + 2W<BR>\n" );
document.write( "324 = 2(2W-6) + 2W<BR>\n" );
document.write( "Distribute<BR>\n" );
document.write( "324 = 4W-12+2W<BR>\n" );
document.write( "324 = 6W-12<BR>\n" );
document.write( "Add 12 to each side<BR>\n" );
document.write( "336 = 6W<BR>\n" );
document.write( "Divide each side by 6<BR>\n" );
document.write( "width = 56<BR>\n" );
document.write( "If the width is 56, then the length is double that 112 minus 6, or 106<BR>\n" );
document.write( "106+106+56+56 = 324 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );