document.write( "Question 896901: Are there two integers with a product of negative 16 and a sum of negative 4? \n" ); document.write( "
Algebra.Com's Answer #543847 by richwmiller(17219)\"\" \"About 
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x*y=-16,
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\n" ); document.write( "\n" ); document.write( "-x^2-4x+16=0
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Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


\"-x%5E2-4%2Ax%2B16\" Start with the given expression.



\"-%28x%5E2%2B4x-16%29\" Factor out the GCF \"-1\".



Now let's try to factor the inner expression \"x%5E2%2B4x-16\"



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Looking at the expression \"x%5E2%2B4x-16\", we can see that the first coefficient is \"1\", the second coefficient is \"4\", and the last term is \"-16\".



Now multiply the first coefficient \"1\" by the last term \"-16\" to get \"%281%29%28-16%29=-16\".



Now the question is: what two whole numbers multiply to \"-16\" (the previous product) and add to the second coefficient \"4\"?



To find these two numbers, we need to list all of the factors of \"-16\" (the previous product).



Factors of \"-16\":

1,2,4,8,16

-1,-2,-4,-8,-16



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to \"-16\".

1*(-16) = -16
2*(-8) = -16
4*(-4) = -16
(-1)*(16) = -16
(-2)*(8) = -16
(-4)*(4) = -16


Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"4\":



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First NumberSecond NumberSum
1-161+(-16)=-15
2-82+(-8)=-6
4-44+(-4)=0
-116-1+16=15
-28-2+8=6
-44-4+4=0




From the table, we can see that there are no pairs of numbers which add to \"4\". So \"x%5E2%2B4x-16\" cannot be factored.



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Answer:



So \"-x%5E2-4%2Ax%2B16\" simply factors to \"-%28x%5E2%2B4x-16%29\"



In other words, \"-x%5E2-4%2Ax%2B16=-%28x%5E2%2B4x-16%29\".

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