document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=896885>Question 896885</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the longest side of the triangular section is 8 feet shorter than twice the shorter side. the third side is 4 feet longer than the shortest side. the perimeter id 60 feet. how long is each side? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #543830 by </B><A HREF=/tutors/aboutme.mpl?userid=JulietG><B>JulietG(1812)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=JulietG><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=JulietG><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=543830\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A + B + C = 60<BR>\n" );
document.write( "A = 2B - 8 (where A is the longest side, and B is the shortest side.  We know C isn't the shortest side from the second sentence.)<BR>\n" );
document.write( "C = B + 4<BR>\n" );
document.write( "Substitute the values of A and C from the bottom equations into the first<BR>\n" );
document.write( "A + B + C = 60<BR>\n" );
document.write( "(2B-8) + B + (B+4) = 60<BR>\n" );
document.write( "4B -4 = 60<BR>\n" );
document.write( "Add 4 to each side<BR>\n" );
document.write( "4B = 64<BR>\n" );
document.write( "Divide each side by 4<BR>\n" );
document.write( "B = 16<BR>\n" );
document.write( "If the shortest side (B) is 16, then A is (2*16)-8, or 24; C is 16+4, or 20<BR>\n" );
document.write( "A = 24<BR>\n" );
document.write( "B = 16<BR>\n" );
document.write( "C = 20 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );